Optimal. Leaf size=553 \[ \frac{\left (b-\sqrt{4 a c+b^2}\right ) \sqrt{\sqrt{4 a c+b^2}+b} \sqrt{1-\frac{2 c x^2}{b-\sqrt{4 a c+b^2}}} \sqrt{1-\frac{2 c x^2}{\sqrt{4 a c+b^2}+b}} \left (\frac{2 c \left (4 a b e^3+15 a c d e^2+15 c^2 d^3\right )}{b-\sqrt{4 a c+b^2}}+e \left (3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )\right ) \text{EllipticF}\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{\sqrt{4 a c+b^2}+b}}\right ),\frac{\sqrt{4 a c+b^2}+b}{b-\sqrt{4 a c+b^2}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}-\frac{e \left (b-\sqrt{4 a c+b^2}\right ) \sqrt{\sqrt{4 a c+b^2}+b} \sqrt{1-\frac{2 c x^2}{b-\sqrt{4 a c+b^2}}} \sqrt{1-\frac{2 c x^2}{\sqrt{4 a c+b^2}+b}} \left (3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{b+\sqrt{b^2+4 a c}}}\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}-\frac{e^2 x \sqrt{a+b x^2-c x^4} (4 b e+15 c d)}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c} \]
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Rubi [A] time = 1.27979, antiderivative size = 553, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.222, Rules used = {1206, 1679, 1202, 524, 424, 419} \[ \frac{\left (b-\sqrt{4 a c+b^2}\right ) \sqrt{\sqrt{4 a c+b^2}+b} \sqrt{1-\frac{2 c x^2}{b-\sqrt{4 a c+b^2}}} \sqrt{1-\frac{2 c x^2}{\sqrt{4 a c+b^2}+b}} \left (\frac{2 c \left (4 a b e^3+15 a c d e^2+15 c^2 d^3\right )}{b-\sqrt{4 a c+b^2}}+e \left (3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right )\right ) F\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{b+\sqrt{b^2+4 a c}}}\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}-\frac{e \left (b-\sqrt{4 a c+b^2}\right ) \sqrt{\sqrt{4 a c+b^2}+b} \sqrt{1-\frac{2 c x^2}{b-\sqrt{4 a c+b^2}}} \sqrt{1-\frac{2 c x^2}{\sqrt{4 a c+b^2}+b}} \left (3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{b+\sqrt{b^2+4 a c}}}\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}-\frac{e^2 x \sqrt{a+b x^2-c x^4} (4 b e+15 c d)}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c} \]
Antiderivative was successfully verified.
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Rule 1206
Rule 1679
Rule 1202
Rule 524
Rule 424
Rule 419
Rubi steps
\begin{align*} \int \frac{\left (d+e x^2\right )^3}{\sqrt{a+b x^2-c x^4}} \, dx &=-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c}-\frac{\int \frac{-5 c d^3-3 e \left (5 c d^2+a e^2\right ) x^2-e^2 (15 c d+4 b e) x^4}{\sqrt{a+b x^2-c x^4}} \, dx}{5 c}\\ &=-\frac{e^2 (15 c d+4 b e) x \sqrt{a+b x^2-c x^4}}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c}+\frac{\int \frac{15 c^2 d^3+15 a c d e^2+4 a b e^3+e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right ) x^2}{\sqrt{a+b x^2-c x^4}} \, dx}{15 c^2}\\ &=-\frac{e^2 (15 c d+4 b e) x \sqrt{a+b x^2-c x^4}}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c}+\frac{\left (\sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}\right ) \int \frac{15 c^2 d^3+15 a c d e^2+4 a b e^3+e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right ) x^2}{\sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}} \, dx}{15 c^2 \sqrt{a+b x^2-c x^4}}\\ &=-\frac{e^2 (15 c d+4 b e) x \sqrt{a+b x^2-c x^4}}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c}-\frac{\left (\left (b-\sqrt{b^2+4 a c}\right ) e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right ) \sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}\right ) \int \frac{\sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}}}{\sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}} \, dx}{30 c^3 \sqrt{a+b x^2-c x^4}}+\frac{\left (\left (b-\sqrt{b^2+4 a c}\right ) \left (\frac{2 c \left (15 c^2 d^3+15 a c d e^2+4 a b e^3\right )}{b-\sqrt{b^2+4 a c}}+e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right )\right ) \sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}\right ) \int \frac{1}{\sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}}} \, dx}{30 c^3 \sqrt{a+b x^2-c x^4}}\\ &=-\frac{e^2 (15 c d+4 b e) x \sqrt{a+b x^2-c x^4}}{15 c^2}-\frac{e^3 x^3 \sqrt{a+b x^2-c x^4}}{5 c}-\frac{\left (b-\sqrt{b^2+4 a c}\right ) \sqrt{b+\sqrt{b^2+4 a c}} e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right ) \sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}} E\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{b+\sqrt{b^2+4 a c}}}\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}+\frac{\left (b-\sqrt{b^2+4 a c}\right ) \sqrt{b+\sqrt{b^2+4 a c}} \left (\frac{2 c \left (15 c^2 d^3+15 a c d e^2+4 a b e^3\right )}{b-\sqrt{b^2+4 a c}}+e \left (45 c^2 d^2+8 b^2 e^2+3 c e (10 b d+3 a e)\right )\right ) \sqrt{1-\frac{2 c x^2}{b-\sqrt{b^2+4 a c}}} \sqrt{1-\frac{2 c x^2}{b+\sqrt{b^2+4 a c}}} F\left (\sin ^{-1}\left (\frac{\sqrt{2} \sqrt{c} x}{\sqrt{b+\sqrt{b^2+4 a c}}}\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )}{30 \sqrt{2} c^{7/2} \sqrt{a+b x^2-c x^4}}\\ \end{align*}
Mathematica [C] time = 2.47424, size = 596, normalized size = 1.08 \[ \frac{i \sqrt{2} \sqrt{\frac{\sqrt{4 a c+b^2}+b-2 c x^2}{\sqrt{4 a c+b^2}+b}} \sqrt{\frac{\sqrt{4 a c+b^2}-b+2 c x^2}{\sqrt{4 a c+b^2}-b}} \left (15 c^2 d e \left (3 d \sqrt{4 a c+b^2}-2 a e-3 b d\right )+c e^2 \left (30 b d \sqrt{4 a c+b^2}+9 a e \sqrt{4 a c+b^2}-17 a b e-30 b^2 d\right )+8 b^2 e^3 \left (\sqrt{4 a c+b^2}-b\right )-30 c^3 d^3\right ) \text{EllipticF}\left (i \sinh ^{-1}\left (\sqrt{2} x \sqrt{-\frac{c}{\sqrt{4 a c+b^2}+b}}\right ),\frac{\sqrt{4 a c+b^2}+b}{b-\sqrt{4 a c+b^2}}\right )-i \sqrt{2} e \left (\sqrt{4 a c+b^2}-b\right ) \sqrt{\frac{\sqrt{4 a c+b^2}+b-2 c x^2}{\sqrt{4 a c+b^2}+b}} \sqrt{\frac{\sqrt{4 a c+b^2}-b+2 c x^2}{\sqrt{4 a c+b^2}-b}} \left (3 c e (3 a e+10 b d)+8 b^2 e^2+45 c^2 d^2\right ) E\left (i \sinh ^{-1}\left (\sqrt{2} \sqrt{-\frac{c}{b+\sqrt{b^2+4 a c}}} x\right )|\frac{b+\sqrt{b^2+4 a c}}{b-\sqrt{b^2+4 a c}}\right )-4 c e^2 x \sqrt{-\frac{c}{\sqrt{4 a c+b^2}+b}} \left (a+b x^2-c x^4\right ) \left (4 b e+3 c \left (5 d+e x^2\right )\right )}{60 c^3 \sqrt{-\frac{c}{\sqrt{4 a c+b^2}+b}} \sqrt{a+b x^2-c x^4}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.058, size = 1195, normalized size = 2.2 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{3}}{\sqrt{-c x^{4} + b x^{2} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{{\left (e^{3} x^{6} + 3 \, d e^{2} x^{4} + 3 \, d^{2} e x^{2} + d^{3}\right )} \sqrt{-c x^{4} + b x^{2} + a}}{c x^{4} - b x^{2} - a}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (d + e x^{2}\right )^{3}}{\sqrt{a + b x^{2} - c x^{4}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (e x^{2} + d\right )}^{3}}{\sqrt{-c x^{4} + b x^{2} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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